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Use the graoh to answer the question. The graph shows an exponentially rising line passing through (1, 3) and (0, 1) Write the...Question
Use the graph to answer the question.
The graph shows an exponentially rising line passing through (-1, 1/3) and (1, 3/4)
Write the exponential equation shown in the graph.
The graph shows an exponentially rising line passing through (-1, 1/3) and (1, 3/4)
Write the exponential equation shown in the graph.
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Answered by
GPT-4o mini
To find the exponential equation of the form \(y = ab^x\) that passes through the points (-1, 1/3) and (1, 3/4), we can set up a system of equations using the given points.
1. From the point (-1, 1/3):
\[
y = ab^{-1} = \frac{1}{3}
\]
This can be rewritten as:
\[
\frac{a}{b} = \frac{1}{3} \quad \text{(Equation 1)}
\]
2. From the point (1, 3/4):
\[
y = ab^1 = \frac{3}{4}
\]
This gives us:
\[
ab = \frac{3}{4} \quad \text{(Equation 2)}
\]
Now, we can express \(a\) in terms of \(b\) using Equation 1:
\[
a = \frac{1}{3}b
\]
Substituting \(a\) into Equation 2:
\[
\left(\frac{1}{3}b\right)b = \frac{3}{4}
\]
\[
\frac{1}{3}b^2 = \frac{3}{4}
\]
Next, we can multiply both sides by 3 to eliminate the fraction:
\[
b^2 = \frac{3 \times 3}{4} = \frac{9}{4}
\]
Now, taking the square root of both sides:
\[
b = \frac{3}{2} \quad \text{(using the positive root since we are modeling growth)}
\]
Now we can substitute \(b = \frac{3}{2}\) back into Equation 1 to find \(a\):
\[
\frac{a}{\frac{3}{2}} = \frac{1}{3}
\]
Multiplying both sides by \(\frac{3}{2}\):
\[
a = \frac{1}{3} \cdot \frac{3}{2} = \frac{1}{2}
\]
Thus, we have found \(a\) and \(b\):
\[
a = \frac{1}{2}, \quad b = \frac{3}{2}
\]
Finally, the exponential equation is:
\[
y = \frac{1}{2} \left(\frac{3}{2}\right)^x
\]
This is the exponential equation that corresponds to the rising line in the graph given the specified points.
1. From the point (-1, 1/3):
\[
y = ab^{-1} = \frac{1}{3}
\]
This can be rewritten as:
\[
\frac{a}{b} = \frac{1}{3} \quad \text{(Equation 1)}
\]
2. From the point (1, 3/4):
\[
y = ab^1 = \frac{3}{4}
\]
This gives us:
\[
ab = \frac{3}{4} \quad \text{(Equation 2)}
\]
Now, we can express \(a\) in terms of \(b\) using Equation 1:
\[
a = \frac{1}{3}b
\]
Substituting \(a\) into Equation 2:
\[
\left(\frac{1}{3}b\right)b = \frac{3}{4}
\]
\[
\frac{1}{3}b^2 = \frac{3}{4}
\]
Next, we can multiply both sides by 3 to eliminate the fraction:
\[
b^2 = \frac{3 \times 3}{4} = \frac{9}{4}
\]
Now, taking the square root of both sides:
\[
b = \frac{3}{2} \quad \text{(using the positive root since we are modeling growth)}
\]
Now we can substitute \(b = \frac{3}{2}\) back into Equation 1 to find \(a\):
\[
\frac{a}{\frac{3}{2}} = \frac{1}{3}
\]
Multiplying both sides by \(\frac{3}{2}\):
\[
a = \frac{1}{3} \cdot \frac{3}{2} = \frac{1}{2}
\]
Thus, we have found \(a\) and \(b\):
\[
a = \frac{1}{2}, \quad b = \frac{3}{2}
\]
Finally, the exponential equation is:
\[
y = \frac{1}{2} \left(\frac{3}{2}\right)^x
\]
This is the exponential equation that corresponds to the rising line in the graph given the specified points.
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