Asked by d
Determine the order of the following matrix:
open square bracket,
begin matrix
row 1, column 1, minus, 2
row 1, column 2, minus, 9
row 1, column 3, 2
row 1, column 4, minus, 1
row 2, column 1, minus, 2
row 2, column 2, minus, 6
row 2, column 3, 8
row 2, column 4, 4
end matrix
, close square bracket
[
−2
−2
−9
−6
2
8
−1
4
]
open square bracket,
begin matrix
row 1, column 1, minus, 2
row 1, column 2, minus, 9
row 1, column 3, 2
row 1, column 4, minus, 1
row 2, column 1, minus, 2
row 2, column 2, minus, 6
row 2, column 3, 8
row 2, column 4, 4
end matrix
, close square bracket
[
−2
−2
−9
−6
2
8
−1
4
]
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine the order of a matrix, we need to identify the number of rows and columns it contains. The order of a matrix is typically expressed as "rows × columns".
From the given matrix:
\[
\begin{bmatrix}
-2 & -9 & 2 & -1 \\
-2 & -6 & 8 & 4
\end{bmatrix}
\]
we can see that there are 2 rows and 4 columns. Therefore, the order of this matrix is \(2 \times 4\).
From the given matrix:
\[
\begin{bmatrix}
-2 & -9 & 2 & -1 \\
-2 & -6 & 8 & 4
\end{bmatrix}
\]
we can see that there are 2 rows and 4 columns. Therefore, the order of this matrix is \(2 \times 4\).
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