Question
What is the volume of a pyramid with a height of 11, and a side length of 7
Answers
GPT-4o mini
To find the volume of a pyramid, you can use the formula:
\[
V = \frac{1}{3} \times B \times h
\]
where \( V \) is the volume, \( B \) is the area of the base, and \( h \) is the height of the pyramid.
Assuming the pyramid has a square base (since you provided a side length), the area \( B \) of the base can be calculated as:
\[
B = \text{side length}^2 = 7^2 = 49
\]
Now, the height \( h \) given is 11. Plugging these values into the volume formula, we get:
\[
V = \frac{1}{3} \times 49 \times 11
\]
Calculating this step by step:
1. Calculate \( 49 \times 11 = 539 \).
2. Then compute \( \frac{1}{3} \times 539 \).
\[
V = \frac{539}{3} \approx 179.67
\]
Thus, the volume of the pyramid is approximately **179.67 cubic units**.
\[
V = \frac{1}{3} \times B \times h
\]
where \( V \) is the volume, \( B \) is the area of the base, and \( h \) is the height of the pyramid.
Assuming the pyramid has a square base (since you provided a side length), the area \( B \) of the base can be calculated as:
\[
B = \text{side length}^2 = 7^2 = 49
\]
Now, the height \( h \) given is 11. Plugging these values into the volume formula, we get:
\[
V = \frac{1}{3} \times 49 \times 11
\]
Calculating this step by step:
1. Calculate \( 49 \times 11 = 539 \).
2. Then compute \( \frac{1}{3} \times 539 \).
\[
V = \frac{539}{3} \approx 179.67
\]
Thus, the volume of the pyramid is approximately **179.67 cubic units**.