Question
Write an equation for the linear function f such that f(1)= 2 and f (3)=-2 with the fórmulas y-y1=m(x-x1) Support grafically
Answers
Answered by
GPT-4o mini
To find the equation of the linear function \( f(x) \), we will start by determining the slope \( m \) using the two points provided: \( (1, 2) \) and \( (3, -2) \).
### Step 1: Calculate the Slope \( m \)
The formula for the slope \( m \) between two points \( (x_1, y_1) \) and \( (x_2, y_2) \) is:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Substituting the given points \( (1, 2) \) and \( (3, -2) \):
- \( (x_1, y_1) = (1, 2) \)
- \( (x_2, y_2) = (3, -2) \)
We get:
\[
m = \frac{-2 - 2}{3 - 1} = \frac{-4}{2} = -2
\]
### Step 2: Use the Point-Slope Form
Now that we have the slope \( m = -2 \), we can use the point-slope formula \( y - y_1 = m(x - x_1) \) with one of the points, let's choose \( (1, 2) \):
\[
y - 2 = -2(x - 1)
\]
### Step 3: Simplify to Slope-Intercept Form
Now, let's simplify the equation:
\[
y - 2 = -2(x - 1)
\]
\[
y - 2 = -2x + 2
\]
\[
y = -2x + 4
\]
### Linear Function Equation
Thus, the equation of the linear function is:
\[
f(x) = -2x + 4
\]
### Graphical Representation
To graph the function, we can plot the points \( (1, 2) \) and \( (3, -2) \) and draw the line through these points.
1. **Point \( (1, 2) \)**:
- When \( x = 1 \):
\[
f(1) = -2(1) + 4 = 2
\]
2. **Point \( (3, -2) \)**:
- When \( x = 3 \):
\[
f(3) = -2(3) + 4 = -2
\]
Now plot these points on a graph and draw a line through them:
- Point \( (1, 2) \) is above the x-axis at x = 1 and y = 2.
- Point \( (3, -2) \) is below the x-axis at x = 3 and y = -2.
Connecting these points gives you the linear function, which slopes downward due to the negative slope of -2.
### Conclusion
The equation of the linear function is \( f(x) = -2x + 4 \) and it passes through the points \( (1, 2) \) and \( (3, -2) \). You can visualize it by graphing the line based on the points we've calculated.
### Step 1: Calculate the Slope \( m \)
The formula for the slope \( m \) between two points \( (x_1, y_1) \) and \( (x_2, y_2) \) is:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Substituting the given points \( (1, 2) \) and \( (3, -2) \):
- \( (x_1, y_1) = (1, 2) \)
- \( (x_2, y_2) = (3, -2) \)
We get:
\[
m = \frac{-2 - 2}{3 - 1} = \frac{-4}{2} = -2
\]
### Step 2: Use the Point-Slope Form
Now that we have the slope \( m = -2 \), we can use the point-slope formula \( y - y_1 = m(x - x_1) \) with one of the points, let's choose \( (1, 2) \):
\[
y - 2 = -2(x - 1)
\]
### Step 3: Simplify to Slope-Intercept Form
Now, let's simplify the equation:
\[
y - 2 = -2(x - 1)
\]
\[
y - 2 = -2x + 2
\]
\[
y = -2x + 4
\]
### Linear Function Equation
Thus, the equation of the linear function is:
\[
f(x) = -2x + 4
\]
### Graphical Representation
To graph the function, we can plot the points \( (1, 2) \) and \( (3, -2) \) and draw the line through these points.
1. **Point \( (1, 2) \)**:
- When \( x = 1 \):
\[
f(1) = -2(1) + 4 = 2
\]
2. **Point \( (3, -2) \)**:
- When \( x = 3 \):
\[
f(3) = -2(3) + 4 = -2
\]
Now plot these points on a graph and draw a line through them:
- Point \( (1, 2) \) is above the x-axis at x = 1 and y = 2.
- Point \( (3, -2) \) is below the x-axis at x = 3 and y = -2.
Connecting these points gives you the linear function, which slopes downward due to the negative slope of -2.
### Conclusion
The equation of the linear function is \( f(x) = -2x + 4 \) and it passes through the points \( (1, 2) \) and \( (3, -2) \). You can visualize it by graphing the line based on the points we've calculated.
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