To determine how many people can come to play on a given night, we know that there are 19 tables and each table accommodates 4 people. Therefore, the total number of people that can play is:
\[ 4 \times 19 = 76 \]
So, the maximum number of people, \( p \), that can come to play on a given night is given by the inequality:
\[ p \leq 76 \]
Let's now express this in terms of the number of tables:
If we divide the total number of tables (19) by 4 people per table, it shows how many players can be accommodated:
So, the correct inequality that expresses how many people can come to play on a given night is:
\[ p \leq 4 \times 19 \]
The inequality \( p \leq 76 \) can also be derived as:
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You could express total tables and players as a fraction of tables, but it's clearer with total count.
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There isn’t a $$p \leq \frac{19}{4}$$ or b) $$\frac{p}{4} \leq 19$$ (which would imply that there are fewer players based on tables).
The right response amongst the options given simplifies to at maximum players would be summed to complete four at each table, hence:
Final Answer: \( p \leq 76 \) None of the provided options directly translate, but the structure shows the constraints on a value of 76 maximum. Thus, options do not match but reasoning explains upholding maximum on 76 players in scenario outlined.