Question
What is DG° at 298 K for the following reaction?
Pb(s) + PbO2(s) -> 2PbO(s)
Substance
DG°f (kJ/mol) at 298 K
PbO(s)
–187.9
PbO2(s)
–217.3
Pb(s) + PbO2(s) -> 2PbO(s)
Substance
DG°f (kJ/mol) at 298 K
PbO(s)
–187.9
PbO2(s)
–217.3
Answers
Pb(s)
0
Therefore, DG° at 298 K for the reaction is -29.4 kJ/mol.
0
Therefore, DG° at 298 K for the reaction is -29.4 kJ/mol.
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