To rewrite the function \( B(t) = 400(0.9)^{2t + 2} \) in the form \( B(t) = ab^t \), we can take the following steps:
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Factor out constants: Notice that \( 2t + 2 \) can be rewritten as: \[ 2t + 2 = 2(t + 1) \] Therefore, we can rewrite the function as: \[ B(t) = 400(0.9)^{2(t + 1)} = 400(0.9^2)^{t + 1} \]
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Calculate \( 0.9^2 \): Now calculate \( 0.9^2 \): \[ 0.9^2 = 0.81 \] Hence, we can substitute back into the equation: \[ B(t) = 400(0.81)^{t + 1} \]
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Express in terms of \( b^t \): Split \( (0.81)^{t + 1} \) into two parts: \[ B(t) = 400 \cdot 0.81^1 \cdot 0.81^t = 400 \cdot 0.81 \cdot (0.81^t) \]
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Set \( a \) and \( b \): Now we can define: \[ a = 400 \cdot 0.81 = 324 \quad \text{and} \quad b = 0.81 \]
Thus, the function in the form \( B(t) = ab^t \) is:
\[ B(t) = 324(0.81)^t \]