Asked by Hussain

Boyle's law states that if the temperature of a gas remains constant, then PV = c. Where P is the pressure, V is the volume, and c is a constant. Given a quantity of gas at constant temperature, if V is decreasing at a rate of 13 in.^3/s, at what rate is P increasing when
P = 90lb/in.^2 and V = 50 in.^3?

Answers

Answered by Reiny
PV = c
by product rule, implicitly,
dP/dt (V) + dV/dt (P) = 0
sub in the given values, solve for dP/dt
Answered by Anonymous
32
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