To analyze the quadratic function \( y = x^2 - 8x \), we can find the key points: the vertex, x-intercepts, and y-intercept.
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Vertex: The vertex of a quadratic function in the form \( y = ax^2 + bx + c \) can be found using the formula \( x = -\frac{b}{2a} \). Here, \( a = 1 \) and \( b = -8 \).
\[ x = -\frac{-8}{2 \cdot 1} = \frac{8}{2} = 4 \]
Next, we find the y-coordinate of the vertex by substituting \( x = 4 \) back into the equation:
\[ y = (4)^2 - 8(4) = 16 - 32 = -16 \]
So, the vertex is \( (4, -16) \).
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Y-intercept: To find the y-intercept, we set \( x = 0 \):
\[ y = (0)^2 - 8(0) = 0 \]
So the y-intercept is \( (0, 0) \).
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X-intercepts: To find the x-intercepts, we set \( y = 0 \):
\[ 0 = x^2 - 8x \]
Factoring gives us:
\[ x(x - 8) = 0 \]
This gives us two solutions:
\[ x = 0 \quad \text{or} \quad x = 8 \]
Therefore, the x-intercepts are \( (0, 0) \) and \( (8, 0) \).
Now, we can summarize the key points:
- Vertex: \( (4, -16) \)
- X-intercepts: \( (0, 0) \) and \( (8, 0) \)
- Y-intercept: \( (0, 0) \)
From the responses you provided, the correct answer that matches these findings is:
D) x-intercepts: (0,0) (8,0)
y-intercept: (0,0)
vertex: (4,−16)