To express 120 as a product of prime numbers with exponents, we first need to perform the prime factorization of 120.
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Start by dividing by the smallest prime number, which is 2:
- 120 ÷ 2 = 60
- 60 ÷ 2 = 30
- 30 ÷ 2 = 15
So far, we have \(2^3\) (since we divided by 2 three times).
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Now we are left with 15, which is not divisible by 2, so we move to the next prime number, which is 3:
- 15 ÷ 3 = 5
Now we have \(3^1\) (since we divided by 3 once).
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Finally, we are left with 5, which is a prime number itself.
Putting it all together, we have: \[ 120 = 2^3 \times 3^1 \times 5^1 \]
This can be written more concisely as: \[ 120 = 2^3 \times 3 \times 5 \]
Thus, the correct response is: \(2^3 \times 3 \times 5\) (which corresponds to \(2^3 \times 3^1 \times 5^1\)). The notation often omits the exponent of 1 for clarity.
Among the given responses, the correct one is: \(2^3 \times 3 \times 5\)