To find the x-intercept and y-intercept of the equation \(10x + 3y = 90\):
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Finding the x-intercept:
- Set \(y = 0\) in the equation: \[ 10x + 3(0) = 90 \quad \Rightarrow \quad 10x = 90 \quad \Rightarrow \quad x = \frac{90}{10} = 9 \]
- So the x-intercept is \((9, 0)\).
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Finding the y-intercept:
- Set \(x = 0\) in the equation: \[ 10(0) + 3y = 90 \quad \Rightarrow \quad 3y = 90 \quad \Rightarrow \quad y = \frac{90}{3} = 30 \]
- So the y-intercept is \((0, 30)\).
Thus, the x-intercept is \((9, 0)\) and the y-intercept is \((0, 30)\).
The correct response is: The x-intercept is (9,0) and the y-intercept is at (0,30).