Asked by d
Find the inverse function in slope-intercept form (mx+b):
f, of, x, equals, minus, 2, x, plus, 2
f(x)=
−2x+2
Answer
f, to the power minus 1 , left parenthesis, x, right parenthesis, equalsf
−1
(x)=
f, of, x, equals, minus, 2, x, plus, 2
f(x)=
−2x+2
Answer
f, to the power minus 1 , left parenthesis, x, right parenthesis, equalsf
−1
(x)=
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the inverse function of \( f(x) = -2x + 2 \), we can follow these steps:
1. **Replace \( f(x) \) with \( y \)**:
\[
y = -2x + 2
\]
2. **Switch \( x \) and \( y \)**:
\[
x = -2y + 2
\]
3. **Solve for \( y \)**:
\[
x - 2 = -2y
\]
\[
-2y = x - 2
\]
\[
y = -\frac{1}{2}(x - 2)
\]
\[
y = -\frac{1}{2}x + 1
\]
4. **Express the inverse function**:
\[
f^{-1}(x) = -\frac{1}{2}x + 1
\]
Thus, the inverse function in slope-intercept form (mx + b) is:
\[
f^{-1}(x) = -\frac{1}{2}x + 1
\]
1. **Replace \( f(x) \) with \( y \)**:
\[
y = -2x + 2
\]
2. **Switch \( x \) and \( y \)**:
\[
x = -2y + 2
\]
3. **Solve for \( y \)**:
\[
x - 2 = -2y
\]
\[
-2y = x - 2
\]
\[
y = -\frac{1}{2}(x - 2)
\]
\[
y = -\frac{1}{2}x + 1
\]
4. **Express the inverse function**:
\[
f^{-1}(x) = -\frac{1}{2}x + 1
\]
Thus, the inverse function in slope-intercept form (mx + b) is:
\[
f^{-1}(x) = -\frac{1}{2}x + 1
\]
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