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The graph shows the distances traveled by two trains over several hours. Which train is moving at a faster rate? Select from th...Question
The graph shows the distances traveled by two runners over several hours.
Which runner is moving at a faster rate?
Select from the drop-down menu to correctly complete the statement.
Runner
Choose...
is moving at a faster rate.
Graph in the coordinate plane with title distance versus time. Vertical axis is labeled distance in miles. Horizontal axis is labeled time in hours. A ray labeled runner A starts at point begin ordered pair 0 comma 0 end ordered pair and goes through point begin ordered pair 8 comma 5 end ordered pair. A ray labeled runner B starts at point begin ordered pair 0 comma 0 end ordered pair and goes through point begin ordered pair 10 comma 2 end ordered pair.
Which runner is moving at a faster rate?
Select from the drop-down menu to correctly complete the statement.
Runner
Choose...
is moving at a faster rate.
Graph in the coordinate plane with title distance versus time. Vertical axis is labeled distance in miles. Horizontal axis is labeled time in hours. A ray labeled runner A starts at point begin ordered pair 0 comma 0 end ordered pair and goes through point begin ordered pair 8 comma 5 end ordered pair. A ray labeled runner B starts at point begin ordered pair 0 comma 0 end ordered pair and goes through point begin ordered pair 10 comma 2 end ordered pair.
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Answered by
GPT-4o mini
To determine which runner is moving at a faster rate, we can look at the slopes of the lines that represent their distances traveled over time on the graph.
1. **Runner A** starts at (0, 0) and goes through (8, 5). The slope (rate of distance per time) can be calculated as:
\[
\text{slope of Runner A} = \frac{\Delta y}{\Delta x} = \frac{5 - 0}{8 - 0} = \frac{5}{8} \text{ miles per hour.}
\]
2. **Runner B** starts at (0, 0) and goes through (10, 2). The slope can be calculated as:
\[
\text{slope of Runner B} = \frac{\Delta y}{\Delta x} = \frac{2 - 0}{10 - 0} = \frac{2}{10} = \frac{1}{5} \text{ miles per hour.}
\]
Now, we can compare the slopes:
- Runner A: \( \frac{5}{8} \) miles per hour
- Runner B: \( \frac{1}{5} \) miles per hour
To compare these values, we can convert them to decimals:
- \( \frac{5}{8} = 0.625 \) miles per hour
- \( \frac{1}{5} = 0.2 \) miles per hour
Since \( 0.625 > 0.2 \), we can conclude:
**Runner A is moving at a faster rate.**
So, the completed statement is:
**Runner A is moving at a faster rate.**
1. **Runner A** starts at (0, 0) and goes through (8, 5). The slope (rate of distance per time) can be calculated as:
\[
\text{slope of Runner A} = \frac{\Delta y}{\Delta x} = \frac{5 - 0}{8 - 0} = \frac{5}{8} \text{ miles per hour.}
\]
2. **Runner B** starts at (0, 0) and goes through (10, 2). The slope can be calculated as:
\[
\text{slope of Runner B} = \frac{\Delta y}{\Delta x} = \frac{2 - 0}{10 - 0} = \frac{2}{10} = \frac{1}{5} \text{ miles per hour.}
\]
Now, we can compare the slopes:
- Runner A: \( \frac{5}{8} \) miles per hour
- Runner B: \( \frac{1}{5} \) miles per hour
To compare these values, we can convert them to decimals:
- \( \frac{5}{8} = 0.625 \) miles per hour
- \( \frac{1}{5} = 0.2 \) miles per hour
Since \( 0.625 > 0.2 \), we can conclude:
**Runner A is moving at a faster rate.**
So, the completed statement is:
**Runner A is moving at a faster rate.**
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