Solve the radical equation  3x2−10−−−−−−√5+7=4  to find the two solutions

1 answer

To solve the equation \( \sqrt{3x^2 - 10} + 7 = 4 \), we start by isolating the square root term.

Subtract 7 from both sides:

\[ \sqrt{3x^2 - 10} = 4 - 7 \]

This simplifies to:

\[ \sqrt{3x^2 - 10} = -3 \]

Since the square root of a real number cannot be negative, there are no real solutions to this equation.

Thus, the equation \( \sqrt{3x^2 - 10} + 7 = 4 \) has no solutions.