Question
Put these numbers in order from least to greatest.
5.89(89 repeated) (the square root sign)14 5(pie symbol)
5.89(89 repeated) (the square root sign)14 5(pie symbol)
Answers
Answered by
GPT-4o mini
To put the numbers in order from least to greatest, we need to first understand the values of each expression:
1. **5.89(89 repeated)**: This number can be expressed as a decimal. The repeating part means that the digits "89" continue indefinitely. The decimal can be approximated as:
\[
5.89898989... \approx 5.89
\]
But for simplicity, we can keep it as \( 5.89\overline{89} \).
2. **√14**: The square root of 14 is approximately:
\[
\sqrt{14} \approx 3.74
\]
3. **5(π)**: This is equal to \( 5 \times \pi \). Since \(\pi \approx 3.14\), we calculate:
\[
5\pi \approx 5 \times 3.14 = 15.7
\]
Now we can compare the values:
- \( 5.89\overline{89} \approx 5.8989... \)
- \( \sqrt{14} \approx 3.74 \)
- \( 5\pi \approx 15.7 \)
Giving us:
1. \( \sqrt{14} \approx 3.74 \)
2. \( 5.89\overline{89} \approx 5.8989... \)
3. \( 5\pi \approx 15.7 \)
Therefore, the ordered numbers from least to greatest are:
\[
\sqrt{14}, 5.89(89 \text{ repeated}), 5(\pi)
\]
1. **5.89(89 repeated)**: This number can be expressed as a decimal. The repeating part means that the digits "89" continue indefinitely. The decimal can be approximated as:
\[
5.89898989... \approx 5.89
\]
But for simplicity, we can keep it as \( 5.89\overline{89} \).
2. **√14**: The square root of 14 is approximately:
\[
\sqrt{14} \approx 3.74
\]
3. **5(π)**: This is equal to \( 5 \times \pi \). Since \(\pi \approx 3.14\), we calculate:
\[
5\pi \approx 5 \times 3.14 = 15.7
\]
Now we can compare the values:
- \( 5.89\overline{89} \approx 5.8989... \)
- \( \sqrt{14} \approx 3.74 \)
- \( 5\pi \approx 15.7 \)
Giving us:
1. \( \sqrt{14} \approx 3.74 \)
2. \( 5.89\overline{89} \approx 5.8989... \)
3. \( 5\pi \approx 15.7 \)
Therefore, the ordered numbers from least to greatest are:
\[
\sqrt{14}, 5.89(89 \text{ repeated}), 5(\pi)
\]
There are no human answers yet. A form for humans to post answers is coming very soon!