To find the equation of the line passing through the points (1, 60) and (7, 140), we can first determine the slope \( m \) and then use the point-slope form of the equation of a line.
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Calculate the slope \( m \): \[ m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{140 - 60}{7 - 1} = \frac{80}{6} = \frac{40}{3} \]
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Choose a point to use in the point-slope form. We can use the point (1, 60): \[ y - y_1 = m(x - x_1) \quad \Rightarrow \quad y - 60 = \frac{40}{3}(x - 1) \]
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Simplify the equation: \[ y - 60 = \frac{40}{3}x - \frac{40}{3} \] \[ y = \frac{40}{3}x - \frac{40}{3} + 60 \] To combine, convert 60 into thirds: \[ 60 = \frac{180}{3} \] So, \[ y = \frac{40}{3}x - \frac{40}{3} + \frac{180}{3} \] \[ y = \frac{40}{3}x + \frac{140}{3} \]
Therefore, the equation of the line is: \[ y = \frac{40}{3}x + \frac{140}{3} \]
So the correct response is: y = 40/3x + 140/3.