Question
Use the table to answer the question.
x-Value y-Value
1 23
5 27
7 32
11 35
15 39
17 43
Find the correlation coefficient of the data using technology (such as GeoGebra). Round your r-value to two decimal places, if necessary.
(1 point)
r=
x-Value y-Value
1 23
5 27
7 32
11 35
15 39
17 43
Find the correlation coefficient of the data using technology (such as GeoGebra). Round your r-value to two decimal places, if necessary.
(1 point)
r=
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To calculate the correlation coefficient (\(r\)) for the given data points, you can use statistical software or calculators that support correlation calculations, such as Excel, Python, or GeoGebra.
Given the data points from the table:
\[
\begin{array}{|c|c|}
\hline
x & y \\
\hline
1 & 23 \\
5 & 27 \\
7 & 32 \\
11 & 35 \\
15 & 39 \\
17 & 43 \\
\hline
\end{array}
\]
If you were to calculate the correlation coefficient using a tool like GeoGebra or a similar technology, follow these steps:
1. Enter the \(x\) values and \(y\) values into the software.
2. Use the function or tool that calculates the correlation coefficient.
Upon doing the calculation, you should find that the correlation coefficient \(r\) is approximately \(0.98\).
Thus, rounding to two decimal places, the result is:
\[
r \approx 0.98
\]
If you want to confirm this or need further assistance in performing the calculations in a specific software, let me know!
Given the data points from the table:
\[
\begin{array}{|c|c|}
\hline
x & y \\
\hline
1 & 23 \\
5 & 27 \\
7 & 32 \\
11 & 35 \\
15 & 39 \\
17 & 43 \\
\hline
\end{array}
\]
If you were to calculate the correlation coefficient using a tool like GeoGebra or a similar technology, follow these steps:
1. Enter the \(x\) values and \(y\) values into the software.
2. Use the function or tool that calculates the correlation coefficient.
Upon doing the calculation, you should find that the correlation coefficient \(r\) is approximately \(0.98\).
Thus, rounding to two decimal places, the result is:
\[
r \approx 0.98
\]
If you want to confirm this or need further assistance in performing the calculations in a specific software, let me know!
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