Question
Does (–2, –1) make the equation y = x^2 true?
Answers
GPT-4o mini
To determine whether the point \((-2, -1)\) satisfies the equation \(y = x^2\), we need to substitute \(x = -2\) into the equation and see if we obtain \(y = -1\).
1. Start with the equation:
\[
y = x^2
\]
2. Substitute \(x = -2\):
\[
y = (-2)^2
\]
3. Calculate \((-2)^2\):
\[
y = 4
\]
Now we have computed \(y = 4\) for \(x = -2\).
Since the point we are checking is \((-2, -1)\) (where \(y = -1\)), we see that:
\[
4 \neq -1
\]
Therefore, the point \((-2, -1)\) does **not** satisfy the equation \(y = x^2\).
1. Start with the equation:
\[
y = x^2
\]
2. Substitute \(x = -2\):
\[
y = (-2)^2
\]
3. Calculate \((-2)^2\):
\[
y = 4
\]
Now we have computed \(y = 4\) for \(x = -2\).
Since the point we are checking is \((-2, -1)\) (where \(y = -1\)), we see that:
\[
4 \neq -1
\]
Therefore, the point \((-2, -1)\) does **not** satisfy the equation \(y = x^2\).