Asked by kristy
how many drops of 0.5M NaOH are needed to neutralize 10 drops of 1.0M HCl? What would be the pH of the neutral solution?
Answers
Answered by
DrBob222
drops x M = drops x M
HCl + NaOH ==> NaCl + H2O
The pH of the solution is determined by the salt; in this case, neither the Na^+ nor the Cl^- are hydrolyzed; therefore, the pH will be the pH of pure water.
H2O ==> H^+ + OH^-
(H^+)(OH^-) = Kw = 1 x 10^-14
Solve for (H^+)
HCl + NaOH ==> NaCl + H2O
The pH of the solution is determined by the salt; in this case, neither the Na^+ nor the Cl^- are hydrolyzed; therefore, the pH will be the pH of pure water.
H2O ==> H^+ + OH^-
(H^+)(OH^-) = Kw = 1 x 10^-14
Solve for (H^+)
Answered by
bell
1 drop
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