To determine which equation has a solution different from the rest, we need to solve each equation for \(x\).
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Equation: \( -17x - 34 = 14 \)
\[ -17x = 14 + 34 \ -17x = 48 \ x = -\frac{48}{17} \approx -2.82 \]
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Equation: \( -\frac{1}{7}x - \frac{3}{4} = \frac{1}{4} \)
\[ -\frac{1}{7}x = \frac{1}{4} + \frac{3}{4} \ -\frac{1}{7}x = 1 \ x = -7 \]
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Equation: \( 12x - 3 = 12 \)
\[ 12x = 12 + 3 \ 12x = 15 \ x = \frac{15}{12} = \frac{5}{4} = 1.25 \]
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Equation: \( \frac{1}{2}x - 3 = \frac{1}{2} \)
\[ \frac{1}{2}x = \frac{1}{2} + 3 \ \frac{1}{2}x = \frac{1}{2} + \frac{6}{2} \ \frac{1}{2}x = \frac{7}{2} \ x = 7 \]
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Equation: \( 34x + 5 = -14 \)
\[ 34x = -14 - 5 \ 34x = -19 \ x = -\frac{19}{34} \approx -0.56 \]
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Equation: \( -0.35x - 0.52 = 1.93 \)
\[ -0.35x = 1.93 + 0.52 \ -0.35x = 2.45 \ x = -\frac{2.45}{0.35} \approx -7 \]
Now, summarizing the solutions:
- First equation: \( x \approx -2.82 \)
- Second equation: \( x = -7 \)
- Third equation: \( x = 1.25 \)
- Fourth equation: \( x = 7 \)
- Fifth equation: \( x \approx -0.56 \)
- Sixth equation: \( x = -7 \)
The unique solutions are:
- \( -2.82 \)
- \( -7 \) (for both second and sixth equations)
- \( 1.25 \)
- \( 7 \)
- \( -0.56 \)
The equation with the solution that is different from all the rest is: \(12x - 3 = 12\) with solution \(x = 1.25\).