To determine if \( x = -3 \) is a solution to the quadratic equation \( -3x^2 - 9x = 0 \), we need to substitute \( -3 \) into the equation and evaluate it.
Substituting \( x = -3 \):
\[ -3(-3)^2 - 9(-3) = 0 \]
Calculating \( (-3)^2 \) gives \( 9 \):
\[ -3(9) - 9(-3) = 0 \]
This simplifies to:
\[ -27 + 27 = 0 \]
Thus, we have:
\[ 0 = 0 \]
Since the equation holds true, we conclude that \( x = -3 \) is indeed a solution.
The correct explanation is:
Yes, \( x = -3 \) is a solution because substituting it back into the equation results in the following:
\[ -3(-3)^2 - 9(-3) = 0 \implies 0 = 0 \quad \text{True} \]
This verifies that \( x = -3 \) is a valid solution.