To analyze the relationship between the data point (4, 43.6) and the trend line \(y = 6.6x + 13.4\), we first need to calculate the predicted value of \(y\) for \(x = 4\):
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Calculate the predicted value: \[ y = 6.6(4) + 13.4 = 26.4 + 13.4 = 39.8 \]
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Determine the residual: The residual is the difference between the actual value and the predicted value. The actual value at \(x = 4\) is \(43.6\): \[ \text{Residual} = \text{Actual} - \text{Predicted} = 43.6 - 39.8 = 3.8 \]
From this analysis, we can conclude that:
- The residual of the data point (4, 43.6) is 3.8.
- This means the data point is 3.8 units above the trend line.
Now, let's evaluate the statements provided:
- The residual of the data point (4,43.6) is -354.4: False
- The data point (4,43.6) is 297.16 units below the trend line: False
- The data point (4,43.6) is 3.8 units above the trend line: True
- The residual of the data point (4,43.6) is -3.8: False
Thus, the accurate conclusion that Jason can make about the trend line is: The data point (4,43.6) is 3.8 units above the trend line.