Question

3x+2y=15
Y=6x
Solve by substitution

Answer 1

To solve the system of equations using substitution, we start with the two equations:

1. \( 3x + 2y = 15 \)
2. \( y = 6x \)

We can substitute the expression for \( y \) from the second equation into the first equation.

Substituting \( y = 6x \) into \( 3x + 2y = 15 \):

\[
3x + 2(6x) = 15
\]

Now simplify the equation:

\[
3x + 12x = 15
\]
\[
15x = 15
\]

Next, divide both sides by 15 to solve for \( x \):

\[
x = 1
\]

Now that we have \( x \), we can substitute it back into the equation \( y = 6x \) to find \( y \):

\[
y = 6(1) = 6
\]

Thus, the solution to the system of equations is:

\[
(x, y) = (1, 6)
\]

So the final answer is:

\[
\boxed{(1, 6)}
\]