point a is located 0.25 m away from a charge of -2.1 x 10 -9 C. point b is located 0.50 m away from the charge. what is the electric potential difference Vb - Va between these two points?

Answer 1

k q[(1/X1) - (1/X2)], where
k = Coulomb's Law constant,
8.99 × 10^9 N*m^2/C^2
X1 = 0.50 m
X2 = 0.25 M
q = 2.1 x 10^-9 C

The answer will be in N*m or Joules

Answer 2

The answer will be in Volts