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Question 22

An object originally at rest is uniformly accelerated to a speed of 8.0 meters per second in 2.0 seconds. What is the acceleration of the object?

\large acceleration=\frac{v_{final}-v_{initial}}{time}

a
<p>16 m/s2</p>
b
<p>0.25 m/s2</p>
c
<p>4.0 m/s2</p>
d
<p>10. m/s2</p>

1 answer

To find the acceleration of the object, we can use the formula you provided:

\[ \text{acceleration} = \frac{v_{final} - v_{initial}}{time} \]

Given:

  • \( v_{final} = 8.0 , \text{m/s} \)
  • \( v_{initial} = 0 , \text{m/s} \) (since the object is originally at rest)
  • \( time = 2.0 , \text{s} \)

Now, plugging the values into the formula:

\[ \text{acceleration} = \frac{8.0 , \text{m/s} - 0 , \text{m/s}}{2.0 , \text{s}} = \frac{8.0 , \text{m/s}}{2.0 , \text{s}} = 4.0 , \text{m/s}^2 \]

So, the acceleration of the object is:

\[ \text{acceleration} = 4.0 , \text{m/s}^2 \]

The correct answer is:

c \(4.0 , \text{m/s}^2\)