Andrew picks three words from a dictionary every week and has listed 24 words. He has been doing this for 8 weeks.
Which of the following can be represented by the equation 3x = 24
3
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=
24
?(1 point)
Responses
A survey was conducted to determine the favorite subject of seventh grade students. One-third of all surveyed, or 24 students, said math is their favorite subject. How many students were surveyed?
A survey was conducted to determine the favorite subject of seventh grade students. One-third of all surveyed, or 24 students, said math is their favorite subject. How many students were surveyed?
The cost of a pair of shoes is three times the cost of a shirt. If the cost of the shirt is $24, how much does the pair of shoes cost?
The cost of a pair of shoes is three times the cost of a shirt. If the cost of the shirt is $24, how much does the pair of shoes cost?
Andrew picks three words from a dictionary every week and lists them in his notebook. So far, he has listed 24 words. How many weeks has Andrew been doing this?
Andrew picks three words from a dictionary every week
just the answer
11 answers
12
°
in 5 hours. The temperature dropped the same amount every hour. Complete the equation that represents the amount of change, x
𝑥
, of temperature every hour and solve this equation.(1 point)
5x=
5
𝑥
=
The temperature decreased by °
°
every hour.
To solve for the amount of change in temperature, \( x \), every hour, we start with the equation that represents the total drop in temperature over 5 hours:
\[ 5x = 12 \]
Now, to solve for \( x \):
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Divide both sides by 5:
\[ x = \frac{12}{5} \]
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Simplifying \( \frac{12}{5} \) gives:
\[ x = 2.4 \]
Thus, the temperature decreased by \( 2.4° \) every hour.
−
7
?(1 point)
Responses
5x+11=−24
5
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+
11
=
−
24
5 x plus 11 equals negative 24
−3x−8=−29
−
3
𝑥
−
8
=
−
29
negative 3 x minus 8 equals negative 29
4x−23=5
4
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−
23
=
5
4 x minus 23 equals 5
−x+3=−4
To determine which equation has a solution of \( x = -7 \), we will substitute \( -7 \) into each equation and see if it satisfies them.
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For \( 5x + 11 = -24 \): \[ 5(-7) + 11 = -35 + 11 = -24 \quad \text{(True)} \]
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For \( -3x - 8 = -29 \): \[ -3(-7) - 8 = 21 - 8 = 13 \quad \text{(False)} \]
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For \( 4x - 23 = 5 \): \[ 4(-7) - 23 = -28 - 23 = -51 \quad \text{(False)} \]
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For \( -x + 3 = -4 \): \[ -(-7) + 3 = 7 + 3 = 10 \quad \text{(False)} \]
The only equation that has a solution of \( x = -7 \) is:
\( 5x + 11 = -24 \).
Responses
12x−3=12
1
2
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−
3
=
1
2
Start Fraction 1 over 2 End Fraction x minus 3 equals Start Fraction 1 over 2 End Fraction
34x+5=−14
3
4
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+
5
=
−
1
4
Start Fraction 3 over 4 End Fraction x plus 5 equals negative Start Fraction 1 over 4 End Fraction
−0.35x−0.52=1.93
−
0.35
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−
0.52
=
1.93
negative 0.35 x minus 0.52 equals 1.93
−17x−34=14
To find which equation has a solution different from the rest, we will solve each equation individually.
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For \( 12x - 3 = 12 \): \[ 12x = 12 + 3 \ 12x = 15 \ x = \frac{15}{12} = \frac{5}{4} = 1.25 \]
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For \( \frac{3}{4}x + 5 = -\frac{1}{4} \): \[ \frac{3}{4}x = -\frac{1}{4} - 5 \ \frac{3}{4}x = -\frac{1}{4} - \frac{20}{4} \ \frac{3}{4}x = -\frac{21}{4} \ x = -\frac{21}{4} \cdot \frac{4}{3} \ x = -7 \]
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For \( -0.35x - 0.52 = 1.93 \): \[ -0.35x = 1.93 + 0.52 \ -0.35x = 2.45 \ x = \frac{2.45}{-0.35} \approx -7 \]
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For \( -17x - 34 = 14 \): \[ -17x = 14 + 34 \ -17x = 48 \ x = \frac{48}{-17} \approx -2.82 \]
Summary of Solutions:
- \( 12x - 3 = 12 \) gives \( x = 1.25 \)
- \( \frac{3}{4}x + 5 = -\frac{1}{4} \) gives \( x = -7 \)
- \( -0.35x - 0.52 = 1.93 \) gives \( x \approx -7 \)
- \( -17x - 34 = 14 \) gives \( x \approx -2.82 \)
Conclusion:
The equation that has a solution different from the rest is \( 12x - 3 = 12 \), which yields \( x = 1.25 \). All the other equations result in solutions around \( -7 \) or \( -2.82 \).
𝑝
𝑥
+
𝑞
=
𝑟
to represent this problem.(2 points)
x
𝑥
+ =
To write an equation in the form \( px + q = r \) where \( x \) represents the number of weekdays Lindsay practiced, we start by identifying the variables and constants involved in the problem.
Let:
- \( x \) = number of weekdays Lindsay practiced
- 30 minutes = amount of time she practices on each weekday
- 50 minutes = amount of time she practices on Saturday
- 140 minutes = total practice time for the week
Lindsay's total practice time for the week can be expressed as: \[ \text{Total Practice Time} = \text{Saturday Practice} + \text{Weekday Practice} \]
This can be formulated as: \[ 50 + 30x = 140 \]
In this equation:
- \( p = 30 \) (the number of minutes she practices each weekday),
- \( q = 50 \) (the minutes spent practicing on Saturday),
- \( r = 140 \) (the total practice time).
Thus, the equation representing this problem is: \[ 30x + 50 = 140 \]
You can solve this equation to find the number of weekdays she practiced.
days
To determine how many days it will take for the baby elephant to reach a weight of 224 pounds, we can set up the following equation.
- Initial weight of the elephant: 150 pounds
- Weight gain per day: 2 pounds
- Target weight: 224 pounds
Let \( d \) represent the number of days the elephant gains weight. The total weight after \( d \) days can be expressed as:
\[ \text{Weight after } d \text{ days} = 150 + 2d \]
We want this weight to equal 224 pounds, so we set up the equation:
\[ 150 + 2d = 224 \]
Now, we can solve for \( d \):
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Subtract 150 from both sides: \[ 2d = 224 - 150 \] \[ 2d = 74 \]
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Divide both sides by 2: \[ d = \frac{74}{2} = 37 \]
Thus, it will take the elephant 37 days to weigh a total of 224 pounds.