Asked by d
How do I work the following question? I found the amu of CaCO3=101.0872g/mol; 2HCL=72.92128g/mol; H2O=18.1582g/mol;CO2=44.0098g/mol; and, CaCl2=110.9834g/mol.
You carefully weigh out 10.00g of powder and add it to 40.50g of solution. You notice bubbles as a reaction takes place. You then weigh the resulting solution and find that it has a mass of 46.40g . The relevant equation is
CaCO_3+2HCL(aq) -> H_2O(l)+CO_2+CaCl_2
What mass of CO_2 was produced in this reaction?
You carefully weigh out 10.00g of powder and add it to 40.50g of solution. You notice bubbles as a reaction takes place. You then weigh the resulting solution and find that it has a mass of 46.40g . The relevant equation is
CaCO_3+2HCL(aq) -> H_2O(l)+CO_2+CaCl_2
What mass of CO_2 was produced in this reaction?
Answers
Answered by
bobpursley
You started with 50.50 of reactants, so you get that same mass of products. Subtract the mass of the solution, and you have the mass of the gas.
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