How do I work the following question? I found the amu of CaCO3=101.0872g/mol; 2HCL=72.92128g/mol; H2O=18.1582g/mol;CO2=44.0098g/mol; and, CaCl2=110.9834g/mol.
You carefully weigh out 10.00g of powder and add it to 40.50g of solution. You notice bubbles as a reaction takes place. You then weigh the resulting solution and find that it has a mass of 46.40g . The relevant equation is
CaCO_3+2HCL(aq) -> H_2O(l)+CO_2+CaCl_2
What mass of CO_2 was produced in this reaction?
1 answer
You started with 50.50 of reactants, so you get that same mass of products. Subtract the mass of the solution, and you have the mass of the gas.
2 answers