To find the equation of the line in standard form that passes through the points \((-1, -4)\) and \((2, 2)\), we can follow these steps:
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Find the slope (m): We use the formula for the slope between two points, which is given by: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \] Here, \((x_1, y_1) = (-1, -4)\) and \((x_2, y_2) = (2, 2)\): \[ m = \frac{2 - (-4)}{2 - (-1)} = \frac{2 + 4}{2 + 1} = \frac{6}{3} = 2 \]
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Use the point-slope form: We can use the point-slope form of the equation, which is: \[ y - y_1 = m(x - x_1) \] Using the slope \(m = 2\) and the point \((2, 2)\): \[ y - 2 = 2(x - 2) \]
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Simplify to slope-intercept form: Distributing the right side: \[ y - 2 = 2x - 4 \] Adding 2 to both sides: \[ y = 2x - 2 \]
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Convert to standard form: We want to convert this to the standard form \(Ax + By = C\): \[ -2x + y = -2 \] To get the coefficients positive, multiply through by -1: \[ 2x - y = 2 \]
So, the equation of the line in standard form is: \[ \boxed{2x - y = 2} \]
This corresponds to one of the responses you provided:
2x - y = 2