To determine which exponential equation contains the points from the input-output table, we need to analyze the values of x and y provided.
We have:
- For \( x = -2 \), \( y = 5,000,000 \)
- For \( x = 1 \), \( y = 0.625 \)
Now letβs evaluate each option:
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Option 1: \( y = 0.0625^x \)
- For \( x = -2 \): \( y = 0.0625^{-2} = \frac{1}{0.0625^2} = \frac{1}{0.00390625} = 256 \) (not equal to 5,000,000)
- For \( x = 1 \): \( y = 0.0625^{1} = 0.0625 \) (not equal to 0.625)
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Option 2: \( y = 125 \cdot (-0.005)^x \)
- For \( x = -2 \): \( y = 125 \cdot (-0.005)^{-2} = 125 \cdot 40000 = 5,000,000 \) (matches)
- For \( x = 1 \): \( y = 125 \cdot (-0.005)^{1} = 125 \cdot -0.005 = -0.625 \) (not equal to 0.625)
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Option 3: \( y = -125 \cdot 0.005^x \)
- For \( x = -2 \): \( y = -125 \cdot (0.005)^{-2} = -125 \cdot 40000 = -5,000,000 \) (not equal to 5,000,000)
- For \( x = 1 \): \( y = -125 \cdot 0.005 = -0.625 \) (not equal to 0.625)
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Option 4: \( y = 125 \cdot 0.005^x \)
- For \( x = -2 \): \( y = 125 \cdot (0.005)^{-2} = 125 \cdot 40000 = 5,000,000 \) (matches)
- For \( x = 1 \): \( y = 125 \cdot 0.005 = 0.625 \) (matches)
Conclusion:
The only candidate that matches both points (5,000,000 for \( x = -2 \) and 0.625 for \( x = 1 \)) is: \( y = 125 \cdot 0.005^x \).