Question
Use the Distributive Property to rewrite the expression (2x − 2)(x − 6).(1 point)
Responses
3x2−10x−8
3
x
2
−
10
x
−
8
3 x squared minus 10 x minus 8
2x2+10x−10
2
x
2
+
10
x
−
10
2 x squared plus 10 x minus 10
2x2−14x+12
2
x
2
−
14
x
+
12
2 x squared minus 14 x plus 12
x2−8x+12
Responses
3x2−10x−8
3
x
2
−
10
x
−
8
3 x squared minus 10 x minus 8
2x2+10x−10
2
x
2
+
10
x
−
10
2 x squared plus 10 x minus 10
2x2−14x+12
2
x
2
−
14
x
+
12
2 x squared minus 14 x plus 12
x2−8x+12
Answers
Answered by
GPT-4o mini
To use the Distributive Property to rewrite the expression \((2x - 2)(x - 6)\), we can apply the formula \(a(b + c) = ab + ac\) and distribute each term in the first parenthesis by each term in the second parenthesis.
Here are the steps:
1. Distribute \(2x\) to both \(x\) and \(-6\):
\[
2x \cdot x = 2x^2
\]
\[
2x \cdot (-6) = -12x
\]
2. Distribute \(-2\) to both \(x\) and \(-6\):
\[
-2 \cdot x = -2x
\]
\[
-2 \cdot (-6) = 12
\]
3. Now combine all these results:
\[
2x^2 - 12x - 2x + 12
\]
4. Combine like terms:
\[
2x^2 - 14x + 12
\]
So, the expression \((2x - 2)(x - 6)\) rewritten using the Distributive Property is:
\[
\boxed{2x^2 - 14x + 12}
\]
This corresponds to the third option in your provided responses.
Here are the steps:
1. Distribute \(2x\) to both \(x\) and \(-6\):
\[
2x \cdot x = 2x^2
\]
\[
2x \cdot (-6) = -12x
\]
2. Distribute \(-2\) to both \(x\) and \(-6\):
\[
-2 \cdot x = -2x
\]
\[
-2 \cdot (-6) = 12
\]
3. Now combine all these results:
\[
2x^2 - 12x - 2x + 12
\]
4. Combine like terms:
\[
2x^2 - 14x + 12
\]
So, the expression \((2x - 2)(x - 6)\) rewritten using the Distributive Property is:
\[
\boxed{2x^2 - 14x + 12}
\]
This corresponds to the third option in your provided responses.
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