Question
A coin is flipped, then a 6-sided die is rolled. What is the probability of getting heads and an even number?
(1 point)
Responses
12
1 2
14
1 4
16
1 6
112
(1 point)
Responses
12
1 2
14
1 4
16
1 6
112
Answers
GPT-4o mini
To find the probability of getting heads when flipping a coin and an even number when rolling a 6-sided die, we can calculate the probabilities for each event separately and then multiply them together since these events are independent.
1. **Probability of getting heads**:
- A coin has two sides: heads and tails.
- Probability of heads = \( \frac{1}{2} \).
2. **Probability of rolling an even number**:
- A 6-sided die has the numbers 1, 2, 3, 4, 5, and 6.
- The even numbers are 2, 4, and 6, which gives us 3 favorable outcomes.
- Probability of rolling an even number = \( \frac{3}{6} = \frac{1}{2} \).
Now, we multiply the probabilities of these two independent events:
\[
P(\text{heads and even number}) = P(\text{heads}) \times P(\text{even number}) = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4}
\]
Thus, the probability of getting heads and an even number is \( \frac{1}{4} \).
The correct answer is **1/4**.
1. **Probability of getting heads**:
- A coin has two sides: heads and tails.
- Probability of heads = \( \frac{1}{2} \).
2. **Probability of rolling an even number**:
- A 6-sided die has the numbers 1, 2, 3, 4, 5, and 6.
- The even numbers are 2, 4, and 6, which gives us 3 favorable outcomes.
- Probability of rolling an even number = \( \frac{3}{6} = \frac{1}{2} \).
Now, we multiply the probabilities of these two independent events:
\[
P(\text{heads and even number}) = P(\text{heads}) \times P(\text{even number}) = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4}
\]
Thus, the probability of getting heads and an even number is \( \frac{1}{4} \).
The correct answer is **1/4**.