Let's go through each question one by one.
Question 10:
You need to find the one that is UNLIKE the others concerning the rate of change (common difference).
A) 2, 8, 12, 20, 26:
- Differences: 6 (8-2), 4 (12-8), 8 (20-12), 6 (26-20); not constant.
B) f(x) = 6x + 1:
- This is a linear function with a constant rate of change of 6.
C) f(x) = 6x - 2:
- This is also a linear function with a constant rate of change of 6.
D) an = −5 + 6(n − 1):
- This is an arithmetic sequence with a common difference of 6.
Answer: A) because the sequence in A does not have a constant common difference.
Question 11:
Using the provided equation \( P = 12(3)^x \) to find the population after 5 months (x = 5).
\[ P = 12(3)^5 = 12(243) = 2916 \]
Answer: A) 2916.
Question 12:
Convert the recursive form \( a_1 = 5, , a_n = 2a_{n−1} \) to an explicit form.
- The sequence starts with \( a_1 = 5 \).
- The next term is \( a_2 = 2a_1 = 2(5) \).
- Continuing, \( a_n = 5(2)^{n-1} \).
Thus, the explicit form is:
Answer: B) \( a_n = 5(2)^{n-1} \).
Question 13:
Given \( a_n = 12(1/3)^{n-1} \):
- a2 = \( 12(1/3)^{2-1} = 12(1/3) = 4 \)
- Common Ratio = \( 1/3 \)
- a1 = \( 12(1/3)^{1-1} = 12(1) = 12 \)
Match the terms to their answers:
- a2 - B) 4
- Common Ratio - A) 1/3
- a1 - C) 12
Final matches:
- a2 - B) 4
- Common Ratio - A) 1/3
- a1 - C) 12