Asked by bruh no
nina's garden is 4 1/5 meters long and 3/10 meter wide. what is the area of nina's garden?
Answers
Answered by
GPT-4o mini
To find the area of Nina's garden, you can use the formula for the area of a rectangle, which is:
\[
\text{Area} = \text{Length} \times \text{Width}
\]
Nina's garden has a length of \(4 \frac{1}{5}\) meters and a width of \(\frac{3}{10}\) meters.
First, convert \(4 \frac{1}{5}\) to an improper fraction:
\[
4 \frac{1}{5} = \frac{4 \times 5 + 1}{5} = \frac{20 + 1}{5} = \frac{21}{5}
\]
Now, the dimensions of the garden are:
- Length = \(\frac{21}{5}\) meters
- Width = \(\frac{3}{10}\) meters
Next, multiply the two fractions together to find the area:
\[
\text{Area} = \frac{21}{5} \times \frac{3}{10} = \frac{21 \times 3}{5 \times 10} = \frac{63}{50}
\]
Now, we can convert \(\frac{63}{50}\) to a mixed number:
\[
\frac{63}{50} = 1 \frac{13}{50}
\]
Thus, the area of Nina's garden is:
\[
\text{Area} = \frac{63}{50} \text{ square meters} \quad \text{or} \quad 1 \frac{13}{50} \text{ square meters}
\]
\[
\text{Area} = \text{Length} \times \text{Width}
\]
Nina's garden has a length of \(4 \frac{1}{5}\) meters and a width of \(\frac{3}{10}\) meters.
First, convert \(4 \frac{1}{5}\) to an improper fraction:
\[
4 \frac{1}{5} = \frac{4 \times 5 + 1}{5} = \frac{20 + 1}{5} = \frac{21}{5}
\]
Now, the dimensions of the garden are:
- Length = \(\frac{21}{5}\) meters
- Width = \(\frac{3}{10}\) meters
Next, multiply the two fractions together to find the area:
\[
\text{Area} = \frac{21}{5} \times \frac{3}{10} = \frac{21 \times 3}{5 \times 10} = \frac{63}{50}
\]
Now, we can convert \(\frac{63}{50}\) to a mixed number:
\[
\frac{63}{50} = 1 \frac{13}{50}
\]
Thus, the area of Nina's garden is:
\[
\text{Area} = \frac{63}{50} \text{ square meters} \quad \text{or} \quad 1 \frac{13}{50} \text{ square meters}
\]