To find out which equation has a different value for \( x \), we need to solve each equation:
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Equation 1: \[ x + 0.875 = 1.5 \implies x = 1.5 - 0.875 = 0.625 \]
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Equation 2:
- The equation \( x + 98 = 74 \) gives: \[ x = 74 - 98 = -24 \]
- The equation \( x + \frac{9}{8} = \frac{7}{4} \) requires finding a common denominator: \[ \frac{7}{4} = \frac{14}{8} \implies x + \frac{9}{8} = \frac{14}{8} \implies x = \frac{14}{8} - \frac{9}{8} = \frac{5}{8} = 0.625 \]
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Equation 3: \[ x - 0.025 = 0.6 \implies x = 0.6 + 0.025 = 0.625 \]
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Equation 4:
- The equation \( x - 78 = -32 \) gives: \[ x = -32 + 78 = 46 \]
- The equation \( x - \frac{7}{8} = -\frac{3}{2} \) gives: \[ -\frac{3}{2} = -\frac{12}{8} \implies x - \frac{7}{8} = -\frac{12}{8} \implies x = -\frac{12}{8} + \frac{7}{8} = -\frac{5}{8} = -0.625 \]
Now we compile the values of \( x \) for each equation:
- Equation 1: \( x = 0.625 \)
- Equation 2: \( x = -24 \) and \( x = 0.625 \)
- Equation 3: \( x = 0.625 \)
- Equation 4: \( x = 46 \) and \( x = -0.625 \)
Conclusion: The equations 1, 2 (second part), and 3 produce the value \( x = 0.625 \) while equations 2 (first part), and 4 have different values, specifically \( x = -24 \) and \( x = 46 \) respectively. Therefore, the equations that produce the different values of \( x \) are:
- \( x + 98 = 74 \) giving \( x = -24 \).
- \( x - 78 = -32 \) giving \( x = 46 \).
Hence, the equation with the unique value for \( x \) from others is \( x + 98 = 74 \).
So, the answer is that the second equation has a different value (from the first and third equations), which can be represented.
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