Question

Subtract 11 19−−√−5 19−−√
.(1 point)

Answer 1

no its not \\sqrt{11} - \sqrt{5}) \sqrt{19} it is 11 \sqrt 19- 5 \sqrt{19}

Answer 2

Simplify 48−−√
.

Answer 3

To subtract \( \sqrt{11} \sqrt{19} - \sqrt{5} \sqrt{19} \), we first factor out the common term \( \sqrt{19} \):

\[
\sqrt{11} \sqrt{19} - \sqrt{5} \sqrt{19} = (\sqrt{11} - \sqrt{5}) \sqrt{19}
\]

Thus, the simplified expression is

\[
(\sqrt{11} - \sqrt{5}) \sqrt{19}
\]

This is the final result. If you have numerical values or more context you would like to discuss, please let me know!

Answer 4

Apologies for the misunderstanding! Let's correctly simplify the expression \( 11\sqrt{19} - 5\sqrt{19} \).

Since both terms have a common factor of \( \sqrt{19} \), we can factor it out:

\[
11\sqrt{19} - 5\sqrt{19} = (11 - 5)\sqrt{19}
\]

This simplifies to:

\[
6\sqrt{19}
\]

So, the final result is:

\[
6\sqrt{19}
\]

Thank you for your patience!

Answer 5

To simplify \( \sqrt{48} \), we can factor 48 into its prime factors:

\[
48 = 16 \times 3 = 4^2 \times 3
\]

Now, we can take the square root of the perfect square \( 16 \):

\[
\sqrt{48} = \sqrt{16 \times 3} = \sqrt{16} \times \sqrt{3} = 4\sqrt{3}
\]

Thus, the simplified form of \( \sqrt{48} \) is:

\[
4\sqrt{3}
\]