.(1 point)
5 answers
To subtract \( \sqrt{11} \sqrt{19} - \sqrt{5} \sqrt{19} \), we first factor out the common term \( \sqrt{19} \):
\[ \sqrt{11} \sqrt{19} - \sqrt{5} \sqrt{19} = (\sqrt{11} - \sqrt{5}) \sqrt{19} \]
Thus, the simplified expression is
\[ (\sqrt{11} - \sqrt{5}) \sqrt{19} \]
This is the final result. If you have numerical values or more context you would like to discuss, please let me know!
Apologies for the misunderstanding! Let's correctly simplify the expression \( 11\sqrt{19} - 5\sqrt{19} \).
Since both terms have a common factor of \( \sqrt{19} \), we can factor it out:
\[ 11\sqrt{19} - 5\sqrt{19} = (11 - 5)\sqrt{19} \]
This simplifies to:
\[ 6\sqrt{19} \]
So, the final result is:
\[ 6\sqrt{19} \]
Thank you for your patience!
To simplify \( \sqrt{48} \), we can factor 48 into its prime factors:
\[ 48 = 16 \times 3 = 4^2 \times 3 \]
Now, we can take the square root of the perfect square \( 16 \):
\[ \sqrt{48} = \sqrt{16 \times 3} = \sqrt{16} \times \sqrt{3} = 4\sqrt{3} \]
Thus, the simplified form of \( \sqrt{48} \) is:
\[ 4\sqrt{3} \]
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