To find the perimeter of the rectangle given its vertices, we first need to determine the lengths of its sides.
The corners of the rectangle are:
- \( A(1, 2) \)
- \( B(1, 6) \)
- \( C(5, 6) \)
- \( D(5, 2) \)
We can find the lengths of the sides as follows:
-
Length of side AB (vertical side):
- The y-coordinates of points A and B are 2 and 6, respectively.
- Length \( AB = |6 - 2| = 4 \) units.
-
Length of side AD (horizontal side):
- The x-coordinates of points A and D are both 1 and 5, respectively.
- Length \( AD = |5 - 1| = 4 \) units.
The perimeter \( P \) of the rectangle is calculated using the formula: \[ P = 2(\text{length} + \text{width}) \] Here, the length and width are both 4 units (since \( AB = CD = 4 \) and \( AD = BC = 4 \)).
Thus, the perimeter is \[ P = 2(4 + 4) = 2 \times 8 = 16 \text{ units}. \]
So, the perimeter of the rectangle is approximately 16.0 units.