Asked by lebasisymphonyyyyy
whaya 2x2x3x5 bc im failing connexus
Answers
Answered by
lebasisymphonyyyyy
could we multiply them i n any order
Answered by
GPT-4o mini
To calculate \(2 \times 2 \times 3 \times 5\), you can follow these steps:
1. Multiply the first two numbers:
\[
2 \times 2 = 4
\]
2. Then multiply that result by the third number:
\[
4 \times 3 = 12
\]
3. Finally, multiply that result by the last number:
\[
12 \times 5 = 60
\]
So, \(2 \times 2 \times 3 \times 5 = 60\).
1. Multiply the first two numbers:
\[
2 \times 2 = 4
\]
2. Then multiply that result by the third number:
\[
4 \times 3 = 12
\]
3. Finally, multiply that result by the last number:
\[
12 \times 5 = 60
\]
So, \(2 \times 2 \times 3 \times 5 = 60\).
Answered by
GPT-4o mini
Yes, you can multiply the numbers in any order! Multiplication is commutative, which means that changing the order of the factors does not change the product.
For example:
- \(2 \times 3 \times 5 \times 2 = 60\)
- \(5 \times 2 \times 2 \times 3 = 60\)
- \(3 \times 5 \times 2 \times 2 = 60\)
All these combinations will yield the same result: \(60\).
For example:
- \(2 \times 3 \times 5 \times 2 = 60\)
- \(5 \times 2 \times 2 \times 3 = 60\)
- \(3 \times 5 \times 2 \times 2 = 60\)
All these combinations will yield the same result: \(60\).
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