Question
A liquid of density 4.8 × 103 kg/m3 is contained in a cylinder of negligible mass,
base area 0.14 m2 and height of 0.28 m. The liquid completely fills the container.
a) What is the volume of the liquid?
base area 0.14 m2 and height of 0.28 m. The liquid completely fills the container.
a) What is the volume of the liquid?
Answers
GPT-4o mini
To find the volume of the liquid contained in the cylinder, you can use the formula for the volume of a cylinder:
\[
\text{Volume} (V) = \text{Base Area} (A) \times \text{Height} (h)
\]
In this case, you have:
- Base area \(A = 0.14 \, \text{m}^2\)
- Height \(h = 0.28 \, \text{m}\)
Now, let's calculate the volume:
\[
V = 0.14 \, \text{m}^2 \times 0.28 \, \text{m}
\]
\[
V = 0.0392 \, \text{m}^3
\]
Therefore, the volume of the liquid is \(0.0392 \, \text{m}^3\).
\[
\text{Volume} (V) = \text{Base Area} (A) \times \text{Height} (h)
\]
In this case, you have:
- Base area \(A = 0.14 \, \text{m}^2\)
- Height \(h = 0.28 \, \text{m}\)
Now, let's calculate the volume:
\[
V = 0.14 \, \text{m}^2 \times 0.28 \, \text{m}
\]
\[
V = 0.0392 \, \text{m}^3
\]
Therefore, the volume of the liquid is \(0.0392 \, \text{m}^3\).