Asked by i 💗 🧋& 🍡
Which of the following equations has the same solution as the equation x + 1/2 = −1/4 ?
Answers
Answered by
i 💗 🧋& 🍡
x + 1/2 = 5/4
x plus Start Fraction 1 over 2 End Fraction equals Start Fraction 5 over 4 End Fraction
x − 1/4 = 1
x minus Start Fraction 1 over 4 End Fraction equals 1
x + 1.5 = 0.75
x plus 1.5 equals 0.75
x − 0.70 = −0.05
x plus Start Fraction 1 over 2 End Fraction equals Start Fraction 5 over 4 End Fraction
x − 1/4 = 1
x minus Start Fraction 1 over 4 End Fraction equals 1
x + 1.5 = 0.75
x plus 1.5 equals 0.75
x − 0.70 = −0.05
Answered by
i 💗 🧋& 🍡
Nick bought groceries for n dollars. He had a coupon for $15.50 off. He paid $34.63 including tax for the groceries he purchased. Which equation represents the original cost of groceries Nick bought? What was this amount?(1 point)
Responses
n + 15.50 = 34.63; the original cost of the groceries Nick bought was $19.13.
n plus 15.50 equals 34.63 ; the original cost of the groceries Nick bought was $19.13.
n + 34.63 = 15.50; the original cost of the groceries Nick bought was $50.13.
n plus 34.63 equals 15.50 ; the original cost of the groceries Nick bought was $50.13.
n − 34.63 = 15.50; the original cost of the groceries Nick bought was $19.13.
n minus 34.63 equals 15.50 ; the original cost of the groceries Nick bought was $19.13.
n − 15.50 = 34.63; the original cost of the groceries Nick bought was $50.13.
Responses
n + 15.50 = 34.63; the original cost of the groceries Nick bought was $19.13.
n plus 15.50 equals 34.63 ; the original cost of the groceries Nick bought was $19.13.
n + 34.63 = 15.50; the original cost of the groceries Nick bought was $50.13.
n plus 34.63 equals 15.50 ; the original cost of the groceries Nick bought was $50.13.
n − 34.63 = 15.50; the original cost of the groceries Nick bought was $19.13.
n minus 34.63 equals 15.50 ; the original cost of the groceries Nick bought was $19.13.
n − 15.50 = 34.63; the original cost of the groceries Nick bought was $50.13.
Answered by
i 💗 🧋& 🍡
Mela wants to buy a pair of shoes that costs $40.99 including tax. She gives the cashier $50 . Which equation can be used to find the amount of change, c , Mela receives? How much is her change?(1 point)
Responses
c − 40.99 = 50; Mela receives $90.99 in change.
c minus 40.99 equals 50 ; Mela receives $90.99 in change.
c + 50 = 40.99; Mela receives $9.01 in change.
c plus 50 equals 40.99 ; Mela receives $9.01 in change.
c − 50 = 40.99; Mela receives $90.99 in change.
c minus 50 equals 40.99 ; Mela receives $90.99 in change.
c + 40.99 = 50; Mela receives $9.01 in change.
Responses
c − 40.99 = 50; Mela receives $90.99 in change.
c minus 40.99 equals 50 ; Mela receives $90.99 in change.
c + 50 = 40.99; Mela receives $9.01 in change.
c plus 50 equals 40.99 ; Mela receives $9.01 in change.
c − 50 = 40.99; Mela receives $90.99 in change.
c minus 50 equals 40.99 ; Mela receives $90.99 in change.
c + 40.99 = 50; Mela receives $9.01 in change.
Answered by
i 💗 🧋& 🍡
Which equation has a different solution than the rest?(1 point)
Responses
x/4=−1
Start Fraction x over 4 End Fraction equals negative 1
x/−2=2
Start Fraction x over negative 2 equals 2
−12x=48
negative 12x equals 48
16x=64
Responses
x/4=−1
Start Fraction x over 4 End Fraction equals negative 1
x/−2=2
Start Fraction x over negative 2 equals 2
−12x=48
negative 12x equals 48
16x=64
Answered by
i 💗 🧋& 🍡
Which of the following equations has a solution of −11/4 ?(1 point)
Responses
−2x=2/11
negative 2 x equals Start Fraction 2 over 11 End Fraction
−2x=11/2
negative 2 x equals Start Fraction 11 over 2 End Fraction
1/2x=−11
Start Fraction 1 over 2 End Fraction x equals negative 11
−1/2x=112
Responses
−2x=2/11
negative 2 x equals Start Fraction 2 over 11 End Fraction
−2x=11/2
negative 2 x equals Start Fraction 11 over 2 End Fraction
1/2x=−11
Start Fraction 1 over 2 End Fraction x equals negative 11
−1/2x=112
Answered by
GPT-4o mini
To determine which equation has the same solution as \( x + \frac{1}{2} = -\frac{1}{4} \), we first need to solve the original equation for \( x \).
1. Start with the original equation:
\[
x + \frac{1}{2} = -\frac{1}{4}
\]
2. Subtract \( \frac{1}{2} \) from both sides:
\[
x = -\frac{1}{4} - \frac{1}{2}
\]
3. To perform the subtraction, convert \( \frac{1}{2} \) to a fraction with a denominator of 4:
\[
\frac{1}{2} = \frac{2}{4}
\]
4. Now, substitute it back into the equation:
\[
x = -\frac{1}{4} - \frac{2}{4} = -\frac{3}{4}
\]
So the solution to the equation \( x + \frac{1}{2} = -\frac{1}{4} \) is \( x = -\frac{3}{4} \).
To find an equivalent equation that has the same solution, you can either manipulate the original equation or use equivalent transformations. Here are examples of possible equivalent equations:
- Multiply both sides of the equation \( x + \frac{1}{2} = -\frac{1}{4} \) by any non-zero number.
- Add or subtract the same quantity from both sides.
- Change the equation to a form of \( ax + b = c \).
If you provide the list of equations, I can help identify which one has the same solution \( x = -\frac{3}{4} \).
1. Start with the original equation:
\[
x + \frac{1}{2} = -\frac{1}{4}
\]
2. Subtract \( \frac{1}{2} \) from both sides:
\[
x = -\frac{1}{4} - \frac{1}{2}
\]
3. To perform the subtraction, convert \( \frac{1}{2} \) to a fraction with a denominator of 4:
\[
\frac{1}{2} = \frac{2}{4}
\]
4. Now, substitute it back into the equation:
\[
x = -\frac{1}{4} - \frac{2}{4} = -\frac{3}{4}
\]
So the solution to the equation \( x + \frac{1}{2} = -\frac{1}{4} \) is \( x = -\frac{3}{4} \).
To find an equivalent equation that has the same solution, you can either manipulate the original equation or use equivalent transformations. Here are examples of possible equivalent equations:
- Multiply both sides of the equation \( x + \frac{1}{2} = -\frac{1}{4} \) by any non-zero number.
- Add or subtract the same quantity from both sides.
- Change the equation to a form of \( ax + b = c \).
If you provide the list of equations, I can help identify which one has the same solution \( x = -\frac{3}{4} \).
Answered by
GPT-4o mini
To find which of the given equations has the same solution as \( x + \frac{1}{2} = -\frac{1}{4} \) (where we previously solved it and got \( x = -\frac{3}{4} \)), let's solve each of the provided equations for \( x \) and check if they yield \( -\frac{3}{4} \).
1. **Equation:** \( x + \frac{1}{2} = \frac{5}{4} \)
Subtract \( \frac{1}{2} \) from both sides:
\[
x = \frac{5}{4} - \frac{1}{2}
\]
Convert \( \frac{1}{2} \) to a fraction with a denominator of 4:
\[
x = \frac{5}{4} - \frac{2}{4} = \frac{3}{4}
\]
2. **Equation:** \( x - \frac{1}{4} = 1 \)
Add \( \frac{1}{4} \) to both sides:
\[
x = 1 + \frac{1}{4} = \frac{4}{4} + \frac{1}{4} = \frac{5}{4}
\]
3. **Equation:** \( x + 1.5 = 0.75 \)
Subtract \( 1.5 \) from both sides (convert \( 1.5 \) to a fraction):
\[
1.5 = \frac{3}{2} \quad \text{(or 1.5 = 1.5)}
\]
\[
x = 0.75 - 1.5 = -0.75
\]
Convert \( -0.75 \) to a fraction:
\[
x = -\frac{3}{4}
\]
4. **Equation:** \( x - 0.70 = -0.05 \)
Add \( 0.70 \) to both sides:
\[
x = -0.05 + 0.70 = 0.65
\]
Convert \( 0.65 \) to a fraction:
\[
x = \frac{65}{100} = \frac{13}{20}
\]
### Summary of the results:
- From \( x + \frac{1}{2} = \frac{5}{4} \), we get \( x = \frac{3}{4} \).
- From \( x - \frac{1}{4} = 1 \), we get \( x = \frac{5}{4} \).
- From \( x + 1.5 = 0.75 \), we get \( x = -\frac{3}{4} \).
- From \( x - 0.70 = -0.05 \), we get \( x = \frac{13}{20} \).
**Conclusion:** The equation \( x + 1.5 = 0.75 \) has the same solution \( x = -\frac{3}{4} \) as the original equation \( x + \frac{1}{2} = -\frac{1}{4} \).
1. **Equation:** \( x + \frac{1}{2} = \frac{5}{4} \)
Subtract \( \frac{1}{2} \) from both sides:
\[
x = \frac{5}{4} - \frac{1}{2}
\]
Convert \( \frac{1}{2} \) to a fraction with a denominator of 4:
\[
x = \frac{5}{4} - \frac{2}{4} = \frac{3}{4}
\]
2. **Equation:** \( x - \frac{1}{4} = 1 \)
Add \( \frac{1}{4} \) to both sides:
\[
x = 1 + \frac{1}{4} = \frac{4}{4} + \frac{1}{4} = \frac{5}{4}
\]
3. **Equation:** \( x + 1.5 = 0.75 \)
Subtract \( 1.5 \) from both sides (convert \( 1.5 \) to a fraction):
\[
1.5 = \frac{3}{2} \quad \text{(or 1.5 = 1.5)}
\]
\[
x = 0.75 - 1.5 = -0.75
\]
Convert \( -0.75 \) to a fraction:
\[
x = -\frac{3}{4}
\]
4. **Equation:** \( x - 0.70 = -0.05 \)
Add \( 0.70 \) to both sides:
\[
x = -0.05 + 0.70 = 0.65
\]
Convert \( 0.65 \) to a fraction:
\[
x = \frac{65}{100} = \frac{13}{20}
\]
### Summary of the results:
- From \( x + \frac{1}{2} = \frac{5}{4} \), we get \( x = \frac{3}{4} \).
- From \( x - \frac{1}{4} = 1 \), we get \( x = \frac{5}{4} \).
- From \( x + 1.5 = 0.75 \), we get \( x = -\frac{3}{4} \).
- From \( x - 0.70 = -0.05 \), we get \( x = \frac{13}{20} \).
**Conclusion:** The equation \( x + 1.5 = 0.75 \) has the same solution \( x = -\frac{3}{4} \) as the original equation \( x + \frac{1}{2} = -\frac{1}{4} \).
Answered by
GPT-4o mini
Let's break down the problem step by step.
1. **Understanding the situation**: Nick bought groceries at an original price of \( n \) dollars. He applied a coupon that gave him a discount of $15.50. After applying the coupon, he paid $34.63 for the groceries.
2. **Setting up the equation**: The equation to represent the situation can be set up based on the relationship between the original price \( n \), the discount from the coupon, and the amount he paid:
\[
n - 15.50 = 34.63
\]
This means that the original cost of the groceries minus the coupon amount equals the amount paid.
3. **Solving for \( n \)**:
To find \( n \), we can rearrange the equation:
\[
n = 34.63 + 15.50
\]
Now, performing the addition:
\[
n = 50.13
\]
So the original cost of the groceries Nick bought was **$50.13**.
### Conclusion:
The correct equation that represents the original cost of groceries Nick bought is:
\[
n - 15.50 = 34.63
\]
And the original cost was **$50.13**.
Thus, the correct response from your list is:
- **n − 15.50 = 34.63; the original cost of the groceries Nick bought was $50.13.**
1. **Understanding the situation**: Nick bought groceries at an original price of \( n \) dollars. He applied a coupon that gave him a discount of $15.50. After applying the coupon, he paid $34.63 for the groceries.
2. **Setting up the equation**: The equation to represent the situation can be set up based on the relationship between the original price \( n \), the discount from the coupon, and the amount he paid:
\[
n - 15.50 = 34.63
\]
This means that the original cost of the groceries minus the coupon amount equals the amount paid.
3. **Solving for \( n \)**:
To find \( n \), we can rearrange the equation:
\[
n = 34.63 + 15.50
\]
Now, performing the addition:
\[
n = 50.13
\]
So the original cost of the groceries Nick bought was **$50.13**.
### Conclusion:
The correct equation that represents the original cost of groceries Nick bought is:
\[
n - 15.50 = 34.63
\]
And the original cost was **$50.13**.
Thus, the correct response from your list is:
- **n − 15.50 = 34.63; the original cost of the groceries Nick bought was $50.13.**
Answered by
GPT-4o mini
To determine the amount of change \( c \) Mela receives after buying a pair of shoes for $40.99 and giving the cashier $50, we can set up the equation based on the relationship between the cash given, the cost of the shoes, and the change received.
1. **Understanding the situation**:
- Mela pays $40.99 for the shoes.
- She gives the cashier $50.
- The change she receives can be calculated by subtracting the cost of the shoes from the amount she gave.
2. **Setting up the equation**:
The equation can be set up as follows:
\[
c = 50 - 40.99
\]
We can rearrange it in the form of an equation:
\[
c + 40.99 = 50
\]
3. **Solving for \( c \)**:
Now, calculate the change she receives:
\[
c = 50 - 40.99 = 9.01
\]
### Conclusion:
The correct equation that can be used to find the amount of change \( c \) Mela receives is:
\[
c + 40.99 = 50
\]
And Mela receives **$9.01** in change.
Thus, the correct response from your list is:
- **c + 40.99 = 50; Mela receives $9.01 in change.**
1. **Understanding the situation**:
- Mela pays $40.99 for the shoes.
- She gives the cashier $50.
- The change she receives can be calculated by subtracting the cost of the shoes from the amount she gave.
2. **Setting up the equation**:
The equation can be set up as follows:
\[
c = 50 - 40.99
\]
We can rearrange it in the form of an equation:
\[
c + 40.99 = 50
\]
3. **Solving for \( c \)**:
Now, calculate the change she receives:
\[
c = 50 - 40.99 = 9.01
\]
### Conclusion:
The correct equation that can be used to find the amount of change \( c \) Mela receives is:
\[
c + 40.99 = 50
\]
And Mela receives **$9.01** in change.
Thus, the correct response from your list is:
- **c + 40.99 = 50; Mela receives $9.01 in change.**
Answered by
GPT-4o mini
To determine which equation has a different solution from the rest, let's solve each equation for \( x \).
1. **Equation:** \(\frac{x}{4} = -1\)
Multiply both sides by 4:
\[
x = -1 \times 4 = -4
\]
2. **Equation:** \(\frac{x}{-2} = 2\)
Multiply both sides by \(-2\):
\[
x = 2 \times -2 = -4
\]
3. **Equation:** \(-12x = 48\)
Divide both sides by \(-12\):
\[
x = \frac{48}{-12} = -4
\]
4. **Equation:** \(16x = 64\)
Divide both sides by 16:
\[
x = \frac{64}{16} = 4
\]
### Summary of solutions:
- From \(\frac{x}{4} = -1\), we get \(x = -4\).
- From \(\frac{x}{-2} = 2\), we get \(x = -4\).
- From \(-12x = 48\), we get \(x = -4\).
- From \(16x = 64\), we get \(x = 4\).
### Conclusion:
The first three equations have the solution \(x = -4\). The last equation \(16x = 64\) has a different solution, \(x = 4\).
Thus, the equation that has a different solution than the rest is:
- **\(16x = 64\)**.
1. **Equation:** \(\frac{x}{4} = -1\)
Multiply both sides by 4:
\[
x = -1 \times 4 = -4
\]
2. **Equation:** \(\frac{x}{-2} = 2\)
Multiply both sides by \(-2\):
\[
x = 2 \times -2 = -4
\]
3. **Equation:** \(-12x = 48\)
Divide both sides by \(-12\):
\[
x = \frac{48}{-12} = -4
\]
4. **Equation:** \(16x = 64\)
Divide both sides by 16:
\[
x = \frac{64}{16} = 4
\]
### Summary of solutions:
- From \(\frac{x}{4} = -1\), we get \(x = -4\).
- From \(\frac{x}{-2} = 2\), we get \(x = -4\).
- From \(-12x = 48\), we get \(x = -4\).
- From \(16x = 64\), we get \(x = 4\).
### Conclusion:
The first three equations have the solution \(x = -4\). The last equation \(16x = 64\) has a different solution, \(x = 4\).
Thus, the equation that has a different solution than the rest is:
- **\(16x = 64\)**.
Answered by
GPT-4o mini
To find which of the following equations has a solution of \(-\frac{11}{4}\), we will solve each equation for \(x\) and check if any of them equal \(-\frac{11}{4}\).
1. **Equation:** \(-2x = \frac{2}{11}\)
Divide both sides by \(-2\):
\[
x = \frac{2/11}{-2} = \frac{2}{-22} = -\frac{1}{11}
\]
2. **Equation:** \(-2x = \frac{11}{2}\)
Divide both sides by \(-2\):
\[
x = \frac{11/2}{-2} = \frac{11}{-4} = -\frac{11}{4}
\]
(This equals the solution we want!)
3. **Equation:** \(\frac{1}{2}x = -11\)
Multiply both sides by 2 to eliminate the fraction:
\[
x = -11 \times 2 = -22
\]
4. **Equation:** \(-\frac{1}{2}x = 112\)
Multiply both sides by \(-2\) to solve for \(x\):
\[
x = 112 \times -2 = -224
\]
### Summary of results:
- The **first equation** yields \(x = -\frac{1}{11}\).
- The **second equation** yields \(x = -\frac{11}{4}\).
- The **third equation** yields \(x = -22\).
- The **fourth equation** yields \(x = -224\).
### Conclusion:
The equation that has a solution of \(-\frac{11}{4}\) is:
- **\(-2x = \frac{11}{2}\)**.
1. **Equation:** \(-2x = \frac{2}{11}\)
Divide both sides by \(-2\):
\[
x = \frac{2/11}{-2} = \frac{2}{-22} = -\frac{1}{11}
\]
2. **Equation:** \(-2x = \frac{11}{2}\)
Divide both sides by \(-2\):
\[
x = \frac{11/2}{-2} = \frac{11}{-4} = -\frac{11}{4}
\]
(This equals the solution we want!)
3. **Equation:** \(\frac{1}{2}x = -11\)
Multiply both sides by 2 to eliminate the fraction:
\[
x = -11 \times 2 = -22
\]
4. **Equation:** \(-\frac{1}{2}x = 112\)
Multiply both sides by \(-2\) to solve for \(x\):
\[
x = 112 \times -2 = -224
\]
### Summary of results:
- The **first equation** yields \(x = -\frac{1}{11}\).
- The **second equation** yields \(x = -\frac{11}{4}\).
- The **third equation** yields \(x = -22\).
- The **fourth equation** yields \(x = -224\).
### Conclusion:
The equation that has a solution of \(-\frac{11}{4}\) is:
- **\(-2x = \frac{11}{2}\)**.
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