Question

2*10*7 in across multiplication commutative property

Answer 1

The commutative property of multiplication states that the order in which you multiply numbers does not affect the product. In other words, \( a \times b = b \times a \).

For the expression \( 2 \times 10 \times 7 \), you can rearrange the factors in any order:

1. **Original order**:
\[
2 \times 10 \times 7
\]

2. **Rearranging**:
\[
10 \times 2 \times 7
\]
or
\[
7 \times 10 \times 2
\]
or
\[
2 \times 7 \times 10
\]

3. **Calculating the product**:
Regardless of the order, the product will remain the same:
\[
2 \times 10 = 20 \\
20 \times 7 = 140
\]

So, \( 2 \times 10 \times 7 = 140 \).

You can verify that all rearrangements will yield the same result:
- \( 10 \times 2 = 20 \) and \( 20 \times 7 = 140 \)
- \( 7 \times 10 = 70 \) and \( 70 \times 2 = 140 \)
- \( 2 \times 7 = 14 \) and \( 14 \times 10 = 140 \)

Thus, the commutative property holds true for this multiplication. The final product remains \( 140 \) regardless of the order of multiplication.