Use the table of the masses of several objects to answer the question. Object Mass (grams) paper clip 1.0 penny 2.5 book 860 cereal box 500 small pot 1,200 Between which two objects is gravitational attraction the greatest if placed 1 meter apart? (1 point) Responses between the paper clip and the penny between the paper clip and the penny between the book and the cereal box between the book and the cereal box between the small pot and the book between the small pot and the book between the penny and the small pot.

1 answer

Gravitational attraction between two objects is determined by their masses and the distance between them, according to the formula for gravitational force:

\[ F = G \frac{m_1 m_2}{r^2} \]

where \( F \) is the gravitational force, \( G \) is the gravitational constant, \( m_1 \) and \( m_2 \) are the masses of the objects, and \( r \) is the distance between them.

To find the greatest gravitational attraction between the given objects when placed 1 meter apart, we can calculate the product of the masses for each pair of objects:

  1. Paper clip (1.0g) and Penny (2.5g) \[ 1.0 \times 2.5 = 2.5 \]

  2. Paper clip (1.0g) and Book (860g) \[ 1.0 \times 860 = 860 \]

  3. Paper clip (1.0g) and Cereal box (500g) \[ 1.0 \times 500 = 500 \]

  4. Paper clip (1.0g) and Small pot (1,200g) \[ 1.0 \times 1,200 = 1,200 \]

  5. Penny (2.5g) and Book (860g) \[ 2.5 \times 860 = 2,150 \]

  6. Penny (2.5g) and Cereal box (500g) \[ 2.5 \times 500 = 1,250 \]

  7. Penny (2.5g) and Small pot (1,200g) \[ 2.5 \times 1,200 = 3,000 \]

  8. Book (860g) and Cereal box (500g) \[ 860 \times 500 = 430,000 \]

  9. Book (860g) and Small pot (1,200g) \[ 860 \times 1,200 = 1,032,000 \]

  10. Cereal box (500g) and Small pot (1,200g) \[ 500 \times 1,200 = 600,000 \]

The highest product of masses results from the Book (860g) and Small pot (1,200g) pair, which gives: \[ 860 \times 1,200 = 1,032,000 \]

Therefore, the gravitational attraction is greatest between the Small pot and the Book.