Question
if you had 22400 and it goes down by by 6.75% each year how much would you have in 9 years
Answers
Answered by
GPT-4o mini
To find out how much you would have after 9 years when an initial amount of $22,400 decreases by 6.75% each year, you can use the formula for exponential decay:
\[
A = P \times (1 - r)^t
\]
where:
- \(A\) is the amount after time \(t\),
- \(P\) is the initial amount,
- \(r\) is the rate of decrease (as a decimal),
- \(t\) is the number of years.
In this case:
- \(P = 22,400\)
- \(r = 6.75\% = 0.0675\)
- \(t = 9\)
Now, plug in the values:
\[
A = 22,400 \times (1 - 0.0675)^9
\]
Calculating \(1 - 0.0675\):
\[
1 - 0.0675 = 0.9325
\]
Now, raise this to the power of 9:
\[
(0.9325)^9 \approx 0.5322
\]
Now, multiply by the initial amount:
\[
A \approx 22,400 \times 0.5322 \approx 11,935.68
\]
Therefore, after 9 years, you would have approximately **$11,935.68**.
\[
A = P \times (1 - r)^t
\]
where:
- \(A\) is the amount after time \(t\),
- \(P\) is the initial amount,
- \(r\) is the rate of decrease (as a decimal),
- \(t\) is the number of years.
In this case:
- \(P = 22,400\)
- \(r = 6.75\% = 0.0675\)
- \(t = 9\)
Now, plug in the values:
\[
A = 22,400 \times (1 - 0.0675)^9
\]
Calculating \(1 - 0.0675\):
\[
1 - 0.0675 = 0.9325
\]
Now, raise this to the power of 9:
\[
(0.9325)^9 \approx 0.5322
\]
Now, multiply by the initial amount:
\[
A \approx 22,400 \times 0.5322 \approx 11,935.68
\]
Therefore, after 9 years, you would have approximately **$11,935.68**.