If triangle XYZ ~ triangle AYB, and YB = 25ft, YA = 16ft, and YZ = 88ft, then what is the length of line YX

1 answer

Given that triangle XYZ is similar to triangle AYB, we can use the properties of similar triangles to set up a proportion.

The sides of similar triangles are in proportion. Therefore, we can write the following proportion using the corresponding sides:

\[ \frac{YX}{YA} = \frac{YZ}{YB} \]

Substituting the known values:

\[ \frac{YX}{16} = \frac{88}{25} \]

Now, cross-multiply to solve for \( YX \):

\[ YX \cdot 25 = 88 \cdot 16 \]

Calculating \( 88 \cdot 16 \):

\[ 88 \cdot 16 = 1408 \]

Thus, we have:

\[ 25 \cdot YX = 1408 \]

Now, divide both sides by 25 to find \( YX \):

\[ YX = \frac{1408}{25} = 56.32 \text{ ft} \]

Therefore, the length of line \( YX \) is \( 56.32 \) feet.

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