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Apply the Pythagorean Theorem to find the length between (−1, 6) and (5, −2) . Round your answer to the nearest hundredth, if n...Question
Apply the Pythagorean Theorem to find the length between (−1, 6)
(
−
1
,
6
)
and (5, −2)
(
5
,
−
2
)
. Round your answer to the nearest hundredth, if necessary.(1 point)
Responses

100
100

14
14

10
10

9.22
(
−
1
,
6
)
and (5, −2)
(
5
,
−
2
)
. Round your answer to the nearest hundredth, if necessary.(1 point)
Responses

100
100

14
14

10
10

9.22
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the distance between the points \((-1, 6)\) and \( (5, -2)\) using the Pythagorean Theorem, we can use the distance formula derived from it:
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Here, \((x_1, y_1) = (-1, 6)\) and \((x_2, y_2) = (5, -2)\).
Substituting these values into the formula:
\[
d = \sqrt{(5 - (-1))^2 + (-2 - 6)^2}
\]
Calculating the differences:
- \(x_2 - x_1 = 5 - (-1) = 5 + 1 = 6\)
- \(y_2 - y_1 = -2 - 6 = -8\)
Now substituting these differences back into the formula:
\[
d = \sqrt{(6)^2 + (-8)^2}
\]
Calculating the squares:
\[
d = \sqrt{36 + 64} = \sqrt{100}
\]
Finally, taking the square root:
\[
d = 10
\]
Therefore, the length between the points \((-1, 6)\) and \( (5, -2)\) is \(10\).
The answer is \( \boxed{10} \).
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Here, \((x_1, y_1) = (-1, 6)\) and \((x_2, y_2) = (5, -2)\).
Substituting these values into the formula:
\[
d = \sqrt{(5 - (-1))^2 + (-2 - 6)^2}
\]
Calculating the differences:
- \(x_2 - x_1 = 5 - (-1) = 5 + 1 = 6\)
- \(y_2 - y_1 = -2 - 6 = -8\)
Now substituting these differences back into the formula:
\[
d = \sqrt{(6)^2 + (-8)^2}
\]
Calculating the squares:
\[
d = \sqrt{36 + 64} = \sqrt{100}
\]
Finally, taking the square root:
\[
d = 10
\]
Therefore, the length between the points \((-1, 6)\) and \( (5, -2)\) is \(10\).
The answer is \( \boxed{10} \).
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