Asked by Sara Q
The coordinates of the point NN are left parenthesis, 0, comma, 4, right parenthesis(0,4) and the coordinates of point OO are left parenthesis, 5, comma, 4, right parenthesis, .(5,4). What is the distance, in units, between the point NN and point O, question markO?
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the distance between the points \( N(0, 4) \) and \( O(5, 4) \), we can use the distance formula, which is given by:
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
In this case, we have:
- \( (x_1, y_1) = (0, 4) \)
- \( (x_2, y_2) = (5, 4) \)
Substituting these coordinates into the formula gives:
\[
d = \sqrt{(5 - 0)^2 + (4 - 4)^2}
\]
Calculating inside the square root:
\[
d = \sqrt{(5)^2 + (0)^2} = \sqrt{25 + 0} = \sqrt{25} = 5
\]
Thus, the distance between point \( N \) and point \( O \) is \( \boxed{5} \) units.
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
In this case, we have:
- \( (x_1, y_1) = (0, 4) \)
- \( (x_2, y_2) = (5, 4) \)
Substituting these coordinates into the formula gives:
\[
d = \sqrt{(5 - 0)^2 + (4 - 4)^2}
\]
Calculating inside the square root:
\[
d = \sqrt{(5)^2 + (0)^2} = \sqrt{25 + 0} = \sqrt{25} = 5
\]
Thus, the distance between point \( N \) and point \( O \) is \( \boxed{5} \) units.
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