The coordinates of the point UU are left parenthesis, 9, comma, minus, 1, right parenthesis(9,−1) and the coordinates of point VV are left parenthesis, 2, comma, minus, 1, right parenthesis, .(2,−1). What is the distance, in units, between the point UU and point V, question markV?

Answer 1

To find the distance between the two points $U(9,-1)$ and $V(2,-1)$, we can use the distance formula:

$$d=\sqrt{(x_2-x_1{)}^2+(y_2-y_1{)}^2}$$

Here,

• $U(9,-1)$ corresponds to $(x_1,y_1)=(9,-1)$.
• $V(2,-1)$ corresponds to $(x_2,y_2)=(2,-1)$.

Plugging in the coordinates into the formula:

$$d=\sqrt{(2-9{)}^2+(-1-(-1){)}^2}$$

Calculating the differences:

$$d=\sqrt{(-7{)}^2+(0{)}^2}$$

Calculating the squares:

$$d=\sqrt{49+0}$$

Simplifying:

$$d=\sqrt{49}=7$$

Thus, the distance between the point $U$ and the point $V$ is $7$ units.