Asked by Sara Q
Victoria plans to repaint some classroom bookcases. She has 2 gallons of paint. All of the bookcases are the same size and each requires one eigth
8
1
​
gallon of paint. How many bookcases will she be able to paint?
Answer
Attempt 1 out of 2
To solve, we'll need to
, because we know the SIZE of the groups and the
, but we don't know the
.
8
1
​
gallon of paint. How many bookcases will she be able to paint?
Answer
Attempt 1 out of 2
To solve, we'll need to
, because we know the SIZE of the groups and the
, but we don't know the
.
Answers
Answered by
GPT-4o mini
To determine how many bookcases Victoria can paint, we need to use the amount of paint she has and the amount of paint required for each bookcase.
1. **Total paint available**: 2 gallons
2. **Paint required per bookcase**: \( \frac{1}{8} \) gallon
Next, we can calculate the total number of bookcases that can be painted by dividing the total amount of paint by the amount of paint needed for one bookcase.
\[
\text{Number of bookcases} = \frac{\text{Total paint}}{\text{Paint per bookcase}} = \frac{2 \text{ gallons}}{\frac{1}{8} \text{ gallon per bookcase}}
\]
To divide by a fraction, we multiply by its reciprocal:
\[
\text{Number of bookcases} = 2 \times 8 = 16
\]
So, Victoria will be able to paint **16 bookcases**.
To summarize:
- We approached the problem using division, knowing the total paint and the size of the groups (each bookcase).
- The unknown we solved for was the number of bookcases she can paint.
1. **Total paint available**: 2 gallons
2. **Paint required per bookcase**: \( \frac{1}{8} \) gallon
Next, we can calculate the total number of bookcases that can be painted by dividing the total amount of paint by the amount of paint needed for one bookcase.
\[
\text{Number of bookcases} = \frac{\text{Total paint}}{\text{Paint per bookcase}} = \frac{2 \text{ gallons}}{\frac{1}{8} \text{ gallon per bookcase}}
\]
To divide by a fraction, we multiply by its reciprocal:
\[
\text{Number of bookcases} = 2 \times 8 = 16
\]
So, Victoria will be able to paint **16 bookcases**.
To summarize:
- We approached the problem using division, knowing the total paint and the size of the groups (each bookcase).
- The unknown we solved for was the number of bookcases she can paint.