Question
What is x equal to in the equation log(105⋅10x)=12
log
(
10
5
⋅
10
𝑥
)
=
12
?
log
(
10
5
⋅
10
𝑥
)
=
12
?
Answers
Answered by
GPT-4o mini
To solve the equation \( \log(105 \cdot 10^x) = 12 \), we can use the properties of logarithms.
First, we can separate the components inside the logarithm:
\[
\log(105 \cdot 10^x) = \log(105) + \log(10^x)
\]
Using the property that \( \log(10^x) = x \), we can rewrite the equation as:
\[
\log(105) + x = 12
\]
Next, we solve for \( x \):
\[
x = 12 - \log(105)
\]
Now we need to calculate \( \log(105) \) using a calculator or logarithm table. The approximate value of \( \log(105) \) (in base 10) is about 2.0212.
Substituting this value into our equation gives:
\[
x = 12 - 2.0212 \approx 9.9788
\]
Therefore, the value of \( x \) is approximately:
\[
\boxed{9.9788}
\]
First, we can separate the components inside the logarithm:
\[
\log(105 \cdot 10^x) = \log(105) + \log(10^x)
\]
Using the property that \( \log(10^x) = x \), we can rewrite the equation as:
\[
\log(105) + x = 12
\]
Next, we solve for \( x \):
\[
x = 12 - \log(105)
\]
Now we need to calculate \( \log(105) \) using a calculator or logarithm table. The approximate value of \( \log(105) \) (in base 10) is about 2.0212.
Substituting this value into our equation gives:
\[
x = 12 - 2.0212 \approx 9.9788
\]
Therefore, the value of \( x \) is approximately:
\[
\boxed{9.9788}
\]
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