Asked by Ana

If 0.125 L of a 0.100 M solution of Ba(OH02 are mixed with 0.200 L of a 0.0750 M solution of H3PO4, the following reaction takes place.

3Ba(OH)2 + 2H3PO4 ---> Ba3(PO4)2 + 6H2O

What mass of barium phosphate is formed?

I got 2.51 g Ba3(PO4)2, is that correct? If not could someone explain to me how to go about answering this problem? Please and thank you..

Answers

Answered by DrBob222
That looks ok to me. Very good.
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