If 0.125 L of a 0.100 M solution of Ba(OH02 are mixed with 0.200 L of a 0.0750 M solution of H3PO4, the following reaction takes place.
3Ba(OH)2 + 2H3PO4 ---> Ba3(PO4)2 + 6H2O
What mass of barium phosphate is formed?
I got 2.51 g Ba3(PO4)2, is that correct? If not could someone explain to me how to go about answering this problem? Please and thank you..
1 answer
That looks ok to me. Very good.