Question

-2x=7y-13 ; x=3
Answer to this problem above is y=-2/7x+13/7 : y=1

Answer 1

To solve the equations you provided, we start with the first equation:

\[
-2x = 7y - 13
\]

Given that \( x = 3 \), we can substitute \( x \) into the equation:

\[
-2(3) = 7y - 13
\]

This simplifies to:

\[
-6 = 7y - 13
\]

Now, add 13 to both sides to isolate the term with \( y \):

\[
-6 + 13 = 7y
\]

\[
7 = 7y
\]

Now, divide both sides by 7 to solve for \( y \):

\[
y = 1
\]

Now, regarding the second part of your statement, it appears you were trying to express the equation in slope-intercept form \( y = mx + b \). Let's derive that from the original equation:

Starting from:

\[
-2x = 7y - 13
\]

We arrange it to solve for \( y \):

\[
7y = -2x + 13
\]

Now, divide every term by 7:

\[
y = -\frac{2}{7}x + \frac{13}{7}
\]

So you are correct; the equation can indeed be expressed as:

\[
y = -\frac{2}{7}x + \frac{13}{7}
\]

And we also found \( y = 1 \) when \( x = 3 \).